b) n = 33 and

            p = 0.25

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

For a z-value of -0.13, Table A.5 gives a probability of 0.0517, which is the area between the sample proportion 0.24 and the population proportion 0.25. Therefore